Math, asked by Razly, 1 year ago

the root of the quadratic equation x^2-3X-M (m+3) where m is a constant ​

Answers

Answered by anjumabid2010
3

Answer:

Step-by-step explanation:

x^2 - 3x - m(m+3) = 0

=> x^2 + mx - (m+3)x- m(m+3) = 0

=> x(x+m) - (m+3)(x+m) = 0

=> (x+m) (x-m-3) = 0

x = - m and m+3

Roots are - m and m+3

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