Question

the roots of the equation X2/3+X1/3-2=0​

Answer 1

Answer:

Correct option is

D

1,−8

The given equation is x2/3+x1/3−2=0

Put x1/3=y, then y2+y−2=0

⇒(y−1)(y+2)=0⇒y=1 or y=−2

⇒x1/3=1 or x1/3=−2

∴x=(1)3=1 or x=(−2)3=−8

Hence, the real root of the given equation are 1 & −8.