Math, asked by avikshitchanda, 11 months ago

The roots of the quadratic equation 4x^2 -[5a+1]x+5a=0 are alpha and beeta.if beeta =1+alpha, calculate the possible values of a,alpha,beeta

Answers

Answered by atharvanerkar
8

Answer:

Hi avikshit... here is it correct answer for this question....

Step-by-step explanation:

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Hope it helps you ..... and Don,t forget to mark this answer as brainliest....

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Answered by temporarygirl
0

Hola mate

Here is your answer -

plz refer to the attachment given.

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