Question

The roots of x2+kx+k=0 are real and unequal find k

Answer 1

Answer:if the roots are real and unequal then b2-4ac>0

Step-by-step explanation:

So by putting the value:

B2-4ac>0

(K)2-4*2*k>0

K2-8k>0

K(k-8)>0

K>8

Therefore,the value of k is greater than 8

Answer 2

Answer :

2x+kx+k=0

Comparing equation with ax2+bx+c=0

a=2

b=k

c=k

Delta = b2-4ac

= (2) 2-4XkXk

= 4-4+2k

K=4-4+2

=4-6

= -2

. : k= -2