The second term of a gp is 2/3 and its 5th term is 16/81. its 7th term is
Answers
Answered by
3
let the first term of GP be a and common ratio be r
so the second term of the GP=ar^2-1
2/3=at
the fifth term of the GP =ar^5-1
16/81=ar^4
16/81=ar×r³
16/81=2/3×r³
48/162=r³
24/81=r³
8/27=r³
r=2/3
therefore a=1
the 7th term=ar^6-1
=(2/3)^5
=32/243
please mark me as brain list
so the second term of the GP=ar^2-1
2/3=at
the fifth term of the GP =ar^5-1
16/81=ar^4
16/81=ar×r³
16/81=2/3×r³
48/162=r³
24/81=r³
8/27=r³
r=2/3
therefore a=1
the 7th term=ar^6-1
=(2/3)^5
=32/243
please mark me as brain list
Similar questions