Question

the set of all positive integers which leaves remainder 5 when divided by 7 are​

Answer 1

please follow me

Sorry for bad cameras and hand writing and presentation

PLEASE THANK ME IF THIS ANSWER IS USEFUL TO YOU MY FRIEND. SO THAT I KNOW THAT MY ANSWER IS HELPFUL OR NOT

HOPE THIS HELPS YOU MY FRIEND

Answer 2

Answer:

129

Step-by-step explanation:

Least 3-digit number=100

Greatest 3-digit number=999

Least 3-digit number when divided by 5 leaves remainder as 7=103

Greatest 3-digit number when divided by 5 leaves remainder as 7=999

So, an A.P. is formed in this way:

103, 110, ......., 999

where d =7

Now,

aₙ=999

a=103

We know,

aₙ=a+(n-1)d

⇒999=103+(n-1)7

⇒896=7(n-1)

⇒n-1=128

⇒n=129