Question

The set of all values of m for which mx2-6mx+5m+1>0 is??

Answer 1

Solution:

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Given:

mx² - 6mx + 5m +1 > 0

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To find:

All the possible values of m,.

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=> mx² - 6mx +5m +1 > 0,

=> m(x² - 6x + 5) + 1 > 0,

=> m(x² - 6x + 5) > -1

=> m (x-5)(x-1) > -1

=> ∴ m > $-\frac{1}{(x-5)(x-1)}$..

The value of m is more than $-\frac{1}{(x-5)(x-1)}$ ,.
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