English, asked by prettymeghanas123, 1 year ago

the shape of a garden is rectangular in the middle and semi circular at the ends as shown in the diagram. find the area and the perimeter of this Garden [length of rectangle is 20-(3.5+3.5)m]
see the diagram...​

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Satyam6393: which class
prettymeghanas123: 10th and u
Satyam6393: 11th
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prettymeghanas123: andhra pradesh (vishakapatnam)
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Answers

Answered by piyushgupta2301
5

area of rectangle = l×b

= 13×7

= 91m^2

area of semi circles =2× 22/7 × 3.5 × 3.5 × 1/2

= 38.46m^2

add both

91 + 38.46

121.46m^2 = area of garden

perimeter of rectangle = 2(l+b)

= 2(13+7)

= 40m^2

perimeter of semi circles = πr

= 22/7 × 3.5

= 11

add both

40 + 11

51m^2 = perimeter of garden


Satyam6393: hii meghana
Satyam6393: hlo
piyushgupta2301: how
piyushgupta2301: sorry its not 51 but its 62
piyushgupta2301: becuase i added perimeter of only one semi cirlce
piyushgupta2301: when we add 11 as perimeter of another semi circle
piyushgupta2301: it becomes 62
prettymeghanas123: but back answer is 48
piyushgupta2301: no it isn't possible
piyushgupta2301: send me the pic from where you have seen the answer
Answered by Anonymous
2

Answer:

20 m = Total length.

7 m = Diameter.

7 / 2 = 3.5 m = Radius.

= 20 - ( 3.5 + 3.5 ) = 20 - 7 = 13 m

= 7 m = Breadth.

Length × Breadth = area of rectangular field.

= 13 × 7 = 91 cm²

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