Question

The shape of the compound in which the central atom has 3 bond pairs and 2 lone pairs of electrons is​

Answer 1

Answer:

H=21[V+M−C+A]

where,

H= Number of orbitals involved in hybridization.

V=Valence electrons of the central atom.

M- Number of monovalent atoms linked to a central atom.

C= Charge of a cation.

A= Charge of an anion.

Consider the hybridization and shape of the options:-

A) I3−

H=21[7+2+1]=5.

⇒sp3d hybridized state with 3 lone pairs.

Linear in shape.

It has 2 bond pairs.

Answer 2

Answer:

For 3 bond pairs and 2 lone pairs, hybridization is sp

3

d. Hence, trigonal bipyramidal geometry. The geometry is also called as T-shaped geometry.

Example: clf3