Question

The short and long hands of a clock are 4 cm and 6cm long respectively.
Find the sum of distances travelled by their tips in 2 days.
[Take = 3.14.]
​

Answer 1

Answer:

The tips cover circular paths.

The hour hand covers 4 complete circles in 2 days (48 hours)

Distance = 2 x 22/7 x 4 x 4 = 100.57 cm

The minute hand covers = 48 Circles in 2 days (Each hour = 1 circle)

Distance = 2 x 22/7 x 6 x 48 = 1810.23 cm

Total distance = 100.57 + 1810.23 = 1910.8 cm

hope this will help you

Answer 2

Answer:

Given :

Length of short hand = 4 cm

Length of long hand = 6 cm

We know short hand make 1 revolution in 12 hours while long hand in 1 hour.

Distance travelled by short hand in 48 hours = 4 × 2 π × 4 = 32 π cm

Distance travelled by long hand in 48 hours = 48 × 2 π × 6 = 576 π cm

Total distance travelled = 32 π cm +  576 π cm = 608 π cm

Therefore ,  sum of distances travelled by their tips in two day is 608 π cm.