Question

the side of arectangular park are in the ratio 5:4.if its area is 8000msq .find lemgth,breadth,perimeter,find the cost of fencing it at ₹3.50per meter

Answer 1

let the l=5x and breath =4x
area of rectangle=l×b
8000= 5x × 4x
400=x^2
20=X
so l=100m and b=80 m
perimeter =2 ×180
=360m
cost=3.50×8000
=₹ 28000

Answer 2

let length be 5 x and 4 x
area of rectangle is equal to length into breadth
8000 is equal to 4 x into 5 x
or 5x ×4x
8000 is equal to 20 x to the power 2
400 is equal to x square
20m is equal to X
length is equal to 5 into 20 which is equal to 100m and breadth is equal to 4 into 20 which is equal to 80 m
perimeter is equal to 2 length into length+ breadth
perimeter is equal to 2 into 100 + 80
perimeter is equal to 360 m
fence cost of fencing is equal to rupees 3.50 into 360
cost of fencing is equal to 1260 ruppes