the sides AS of a parallelogram ABCD is produced to any point P.a line through A and parallel toCP meet CB produced at Q and then parallelogram PBQR is completed.show that Ar(ABCD= Ar(PBQR).
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Explanation:
PBQR is completed. Show that ar(ABCD)=ar(PBQR).
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Answer
Let us join AC and PQ.
△ACQ and △AQP are on the same base AQ and between the same parallels AQ and CP.
∴ Area (△ACQ)= Area
(△APQ)
⇒ Area(△ACQ)−Area(△ABQ)= Area(△ACQ)−Area(△ABQ)
⇒ Area (△ABC)= Area (△ABQ) ... (1)
Since AC and PQ are diagonals of parallelograms ABCD and PBQR respectively,
∴ Area (△ABC)=
2
1
Area of parallelogram ABCD ... (2)
Area(△QBP)=
2
1
Area of parallelogram BPRQ ... (3)
From equations (1),(2), and (3), we obtain
2
1
Area of parallelogram ABCD=
2
1
Area of parallelogram BPRQ
∴ Area of parallelogram ABCD= Area of parallelogram
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