Question

The sides of a right angled triangle are 3 ,4,and 5cm then it's area will be​

Answer 1

To Find :

• Area of right angled triangle.

Given :

• Sides of right angled triangle are 3 cm , 4 cm and 5 cm .

By using Pythagoras theorem : -

‹ Hypotenuse² = Base² + perpendicular ² ›

⟶ 5² = 3² + 4²

⟶ 25 = 9 + 16

⟶ 25 = 25

So, side 5 cm is the hypotenuse of the right angled triangle.

〈Area of triangle = 1/2 × base × height〉

⇢ Area of triangle = 1/2 × 3 × 4

⇢ Area of triangle = 1/2 × 12

⇢ Area of triangle = 6cm²

Hence,

• Area of triangle is 6cm²

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Answer 2

Answer:

6cm²

Step-by-step explanation:

Let the assume the three sides as a , b and c respectively.

a = 3cm

b = 4cm

c = 5cm

Perimeter = Sum of all sides of a figure.

Perimeter of ∆ = Sum of all three sides.

Perimeter = a + b + c

Perimeter = ( 3 + 4 + 5) cm

Perimeter = 12cm

Semi Perimeter (s) = Perimeter /2

Semi Perimeter (s) = 12cm/2

Semi Perimeter (s) = 6cm

Using Heron's Formula,

Area = √s (s - a) (s - b) (s - c)

Area = √ 6 (6 - 3) (6 - 4) (6 - 5)

Area = √ 6 X 3 X 2 X 1

Area = √ 3 X 2 X 3 X 2 X 1

Area = 3 X 2

Area = 6cm²

Therefore the area of the ∆ is 6cm²

NOTE : USING HERON'S FORMULA WE CAN FIND THE AREA OF ANY ∆.

HOPE IT HELPS YOU.

THANKS !

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