The sides of a triangle are in the ratio of 1/2 : 1/3 : 1/4. If its perimeter is 52 cm, the length of the smallest side is:
(A) 9 cm
(B) 10 cm
(C) 11 cm
(D) 12 cm
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Hey !!
Let sides of triangle are X/2 , X/3 and X/4.
Perimeter of triangle = 52 cm
X/2 + X/3 + X/4 = 52
6X + 4X + 3X/12 = 52
13X = 624
X = 48 cm.
First side = X/2 = 48/2 = 24 cm
Second side = X/3 = 48/3 = 16 cm.
And
Third side = X/4 = 48/4 = 12 cm.
Smallest side is 12 cm.
Hence,
Option ( D ) is right answer
Let sides of triangle are X/2 , X/3 and X/4.
Perimeter of triangle = 52 cm
X/2 + X/3 + X/4 = 52
6X + 4X + 3X/12 = 52
13X = 624
X = 48 cm.
First side = X/2 = 48/2 = 24 cm
Second side = X/3 = 48/3 = 16 cm.
And
Third side = X/4 = 48/4 = 12 cm.
Smallest side is 12 cm.
Hence,
Option ( D ) is right answer
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