Question

the sides of the cube of the same material are l and 2l respectively the ratio of their resistance will be​

Answer 1

hope this helps you dear.....have a nice day

Answer 2

The ratio of their resistance will be​ $R_1$ : $R_2$ = 1 : 2.

To find : Ratio of the resistance.

Given :

Sides of the cube of the same material are l and 2l.

Formula used :

Specific resistance, P = $\frac{R\times A}{l}$      

Hence, R = $\frac{P\times l}{A}$

Two cubes of the same material has length l and 2l.

Let $R_1$ and  $R_2$ be the resistance of the two cubes.

$l_1$ and $l_2$ be the length of l and 2l.

$R_1$ = $\frac{P\times l_1}{A}$

$R_2$ = $\frac{P\times l_2}{A}$

Comparing $R_1$  and $R_2$, "P" is common where the material is same.

Dividing $R_1$ by $R_2$, we get

$\frac{R_1}{R_2}$ = $\frac{\frac{P\times l_1}{A}}{\frac{P\times l_2}{A}}$

$\frac{R_1}{R_2}$ = $\frac{P\times l_1}{A}\times\frac{P\times l_2}{A}$

Applying $l_1$ and $l_2$ values, we get

$\frac{R_1}{R_2}$ = $\frac{P\times l}{A}\times\frac{A}{P\times2l}$

$\frac{R_1}{R_2}$ = $\frac{1}{2}$

Hence, the ratio is $R_1$ : $R_2$ = 1 : 2.

To learn more...

1. Two wires of same material have lengths l and 2L and cross sectional areas 4A and a respectively . Then what would be the ratio of their resistances

brainly.in/question/9706255    

2. Two copper wire of length l and 2l have radii r and 2r respectively.The ratio of their specific resistance is

brainly.in/question/8525705