the sides of triangle are 8 cm 15 cm and 17 cm find the area of this Triangle
Answers
Answered by
20
let ABC a triangle
AB =17cm
BC =15cm
CA = 8cm
by herons formula =
underroot s(s-a)(s-b)(s-c)
where S is = semi perimeter of triangle
therefore , perimeter of triangle = (sum of all side) = 17+15+8 = 40
semi perimeter =40/2=20
by herons formula
underroot 20(20-17)(20-15)(20-8)
= underroot 20*3*5*12 = underroot 60*60 ( * = sign of multiply )
therefore area of triangle = 60cm2
area of triangle = 1/2 * base x height
1/2 * 17*?=60=120/17 ans
AB =17cm
BC =15cm
CA = 8cm
by herons formula =
underroot s(s-a)(s-b)(s-c)
where S is = semi perimeter of triangle
therefore , perimeter of triangle = (sum of all side) = 17+15+8 = 40
semi perimeter =40/2=20
by herons formula
underroot 20(20-17)(20-15)(20-8)
= underroot 20*3*5*12 = underroot 60*60 ( * = sign of multiply )
therefore area of triangle = 60cm2
area of triangle = 1/2 * base x height
1/2 * 17*?=60=120/17 ans
Answered by
32
hey friend !!!....
it's easy ....☺
The side of triangle are 8 cm ,15 cm ,17 cm..
so,by using herons formula.....
S=1/2(a+b+c)
=>S=1/2(15+8+17)
=>1/2(40)
>20cm....
now formula is ...
【√s(s-a(s-b)(s-c)】
=>√20(20-8)(20-15)(20-17)
=>√5*2*2*2*2*3*5*3
=>5*2*2*3
=>60 cm^2 Ans .
.hope it help you ...bro....<
@Rajukumar☺☺☺
it's easy ....☺
The side of triangle are 8 cm ,15 cm ,17 cm..
so,by using herons formula.....
S=1/2(a+b+c)
=>S=1/2(15+8+17)
=>1/2(40)
>20cm....
now formula is ...
【√s(s-a(s-b)(s-c)】
=>√20(20-8)(20-15)(20-17)
=>√5*2*2*2*2*3*5*3
=>5*2*2*3
=>60 cm^2 Ans .
.hope it help you ...bro....<
@Rajukumar☺☺☺
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