Math, asked by narendrakumar4666, 1 year ago

The sides of triangular park are 51m, 37m, and 20m. Find the area of the field. Also find the cost of laying grass at the rate of rupees 15 per month square

Answers

Answered by iamrav
6

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Answered by wifilethbridge
2

The area of the field is 306 sq.m.The cost of laying grass at the rate of rupees 15 per m square is Rs.4590

Step-by-step explanation:

Sides of triangular park :

a = 51 m

b = 37 m

c = 20 m

Area of triangular park = A= \sqrt{s(s-a)(s-b)(s-c)}

Wheres=\frac{a+b+c}{2}

Substitute the values:

s=\frac{51+37+20}{2}

s=441

Area of field =\sqrt{54(54-51)(54-37)(54-20)}=306 m^2

Cost of laying grass 1 sq.m. = Rs.15

Cost of laying grass 306 sq.m. = 306 \times 15 =Rs.4590

Hence the area of the field is 306 sq.m.The cost of laying grass at the rate of rupees 15 per m square is Rs.4590

#Learn more:

Find the cost of laying Grass in a triangular field of side 50m 65m 65m at the rate of rupees 7 per metre

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