Question

The sides or legs of a right-angled triangle containing the right angle are in the ratio 3:4. If its area
is 1014 sq cm, find the length of its hypotenuse.​

Answer 1

ANSWER᭄

65 cm

EXPLANATION

Let it's leg be 3x and 4x. Then,

Let it's leg be 3x and 4x. Then,according to question,

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^2

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = x

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cm

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know that

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know thatH^2 = P^2 + B^2

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know thatH^2 = P^2 + B^2H^2 = 39^2 + 52^2

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know thatH^2 = P^2 + B^2H^2 = 39^2 + 52^2H^2 = 1521 + 2704

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know thatH^2 = P^2 + B^2H^2 = 39^2 + 52^2H^2 = 1521 + 2704H = √4225

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know thatH^2 = P^2 + B^2H^2 = 39^2 + 52^2H^2 = 1521 + 2704H = √4225H = 65 cm.

Let it's leg be 3x and 4x. Then,according to question,Area of right angle triangle = 1/2 × 3x × 4x1,014 = 6x^21,014/6 = x^2√169 = x13 cm = xHence, first side = 3×13 = 39 cmsecond side = 4×13 = 52 cm.We know thatH^2 = P^2 + B^2H^2 = 39^2 + 52^2H^2 = 1521 + 2704H = √4225H = 65 cm.Hence, the hypotenuse is 65 cm.

Answer 2

Answer:

65 cm.

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