The simple form of 2/√3-√2=
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2/ √3 - √2
by rationalizing denominator ,
2/(√3 - √2 ) ×(√3 + √2 ) / (√3+ √2)
use identity, (a-b) (a+b ) = a^2 - b^2 , in denominator !
2 ( √3 + √2 ) / (√3)^2 - (√2)^2
= 2(√3 + √2 ) / 1
= 2(√3 + √2)
= 2√3 + 2√2
hope it helps!
thank you !
by rationalizing denominator ,
2/(√3 - √2 ) ×(√3 + √2 ) / (√3+ √2)
use identity, (a-b) (a+b ) = a^2 - b^2 , in denominator !
2 ( √3 + √2 ) / (√3)^2 - (√2)^2
= 2(√3 + √2 ) / 1
= 2(√3 + √2)
= 2√3 + 2√2
hope it helps!
thank you !
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