The size of the exterior angle of a regular polygon is inversely proportional to the number
of sides. The exterior angle of a square is 90°.
a) The exterior angle of a regular polygon is 9º. How many sides does it have?
b) If the number of sides of a regular polygon is doubled, by what factor does the exterior
angle change?
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Answer:
40 sides
as square has 4 sides
exterior angle =90°
360/4= 90
polygon
360/x= 9°
x= 360/9
x= 40
no. of sides = 40
as it is given that ext angle is inversely proportional to no. of sides
if x=> 2x
y = 9/2
exterior angle will reduce by half of its value
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