Math, asked by obadyaobadya, 8 months ago

The slope of a line perpendicular to 13x - 7y+1=0 is​

Answers

Answered by daivikdalwadi10
5

Answer:

Step-by-step explanation:

13x+7y=27

13*1+7y=27

13+7y=27

7y=27-13

7y=14

y=2

or

if x = 1

13 + 7y = 27

7y = 27 - 13 = 14

y = 2

Answered by Lucath
20

Answer:

-7/13

Step-by-step explanation:

the slope of a line perpendicular to a given line y=mx+ c is -1/m

here, 13x-7y+1=0

ie 7y=13x + 1

ie y=13x/7 + 1/7

so,m = 13/7

therefore required slope is -7/13

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