The slope of a line perpendicular to 13x - 7y+1=0 is
Answers
Answered by
5
Answer:
Step-by-step explanation:
13x+7y=27
13*1+7y=27
13+7y=27
7y=27-13
7y=14
y=2
or
if x = 1
13 + 7y = 27
7y = 27 - 13 = 14
y = 2
Answered by
20
Answer:
-7/13
Step-by-step explanation:
the slope of a line perpendicular to a given line y=mx+ c is -1/m
here, 13x-7y+1=0
ie 7y=13x + 1
ie y=13x/7 + 1/7
so,m = 13/7
therefore required slope is -7/13
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