The smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively is _____
(Pls tell the answer with step by step explanation)
Answers
L. C. M. of given numbers 20,25,35,40 is 1400
in all cases difference of the number and remainder is 6
so required number is 1400-6=1394
Answer:
Step-by-step explanation:
All divisions given are=
Divisor Remainder
a) 20 14
b) 25 19
c) 35 29
d)40 34
We need to know the Quotient of the divisions:
a) 20 - 14 = 6
b) 25 - 19 = 6
c) 35 - 29 = 6
d) 40 - 34 = 6
So they all have a similar Quotient which is 6
So let's take one division and find out the Dividend using the formula=
Dividend = q*d+r
a) D= 6*20+14
= 120+14
D=134
So, The smallest number which when divided by 20, 25, 35, 40 leaves a remainder of 14, 19, 29 and 34 respectively is 134
Hope this helps !