Question

The solubility of a salt in water is 30gm / 100 gm at 25°C. it increases 10% for every 5°C rise of temperature upto 50°C and then becomes constant. How much amount of same salt is required to make a saturated solution in 300gm of water at 35°C would be
a) 36.3gmb) 108.9gm c) 300gm d) 110gm​

Answer 1

Explanation:

weight of salt = 90 gram,

solubility = 50

sing formula

solubility of solute =

weightofsolventinsaturatedsolution

weightofsoluteinsaturatedsolution

×100

or 50=

weightofsolventinsaturatedsolutio

90gm

×100

so weight of solvent in saturated solution =

50

90gm

×100=180gm

Hence 180 gm of water is required to prepare a saturated solution.