Question

the solution is needed fast , help me out

Answer 1

I hope this answer help you

Answer 2

(a+b+c)³= a³+b³+c³ +3a²(b+c)+3b²(a+c)+3c²(b+a)+6abc

sum of roots
a+b+c=0
sum of product of roots
ab+bc+ca=-5/k
product of roots
abc=-9/k

and we have a³+b³+c³=27
so when we put all the values in the formula

0= 27 -3a³-3b³-3c³ +6(-9/k)
0=27-3(a³+b³+c³) -54/k
54/k=28-3×27
54/k=28-81
54/k=-54
k=-1

HENCE The value of k is -1