Question

The solution of tan^-1 (1+x) + tan^-1 (1-x) = π/2 is

Answer 1

$tan {}^{ - 1} a + tan {}^{ - 1} b = tan {}^{ - 1} a + b \div 1 - ab$
tan^-1{1+x+1-x÷1-(1-x^2)}=π/2
2/x^2=tan-1(π/2)
2/x^2=infinity
By this we can say x=0