Question

The solution set of inequation (x^2-x-12)>0
is given by

Answer 1

${x}^{2} - x - 12 > 0 \\ \\ {x}^{2} - 4x + 3x - 12 > 0 \\ \\ x(x - 4) + 3(x - 4) > 0 \\ \\ (x + 3)(x - 4) > 0 \\ \\ x < < ( - \infty \: \: - 3)u(4 \: \: \: \infty )$

hope it helps

Answer 2

hope this answer helps you and plz follow me