Question

the speed of a train changes from 36 km per hour to 72 kilometre per hour in 10 second the distance travelled during this time is

Answer 1

36km/h = 36*5/18 m/s = 10m/s
72km/h = 72*5/18 m/s = 20m/s

a = (v - u)/t
a = (20 - 10)/10
a = 10/10
a = 1m/s^2

S = ut + 0.5at^2
S = 10*10 + 0.5*1*10^2
S = 100 + 50
S = 150m

Distance travelled during this time is 150m

Answer 2

initial velocity=10mpersecond
final velocity=20mper sec
time=10s
Distance={final velocity+initial velocity}/2 x time
30/2×10=150m