Question

the speed of a train changes from 36 km per hour to 72 km per hour in 10 seconds calculate the distance travel during this time.

Answer 1

We can first find the acceleration by using eq. of motion
v = u + at
Then we can find the distance covered by applying another formula i.e.
v^2 - u^2 = 2as

All the best..✌

Answer 2

u=10m/s

v=20m/s

t=10

a= v - u/t                                                                                                                                  

20-10/10 = 1m/s²

v² - u² = 2as

(20)² - (10)² = 2×1×s

= 300 = 2s

s = 300/2

=150m