the speed of sound in aur at 0°C is 332m/s .If it increases at the rate of 0.6m/s per degree what will be the temperature when the velocity has increased to 344m/s .
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The speed of sound in air at 0℃ = 332m/s
If it increases at the rate of 0.6m/s per degree,
Speed at x℃ = (332 + 0.6x)℃
Thus 344 = 332 + 0.6x
344 - 332 = 0.6x
12 = 0.6x
x = 12/ 0.6 = 20℃
Temperature is 20℃
If it increases at the rate of 0.6m/s per degree,
Speed at x℃ = (332 + 0.6x)℃
Thus 344 = 332 + 0.6x
344 - 332 = 0.6x
12 = 0.6x
x = 12/ 0.6 = 20℃
Temperature is 20℃
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