Question

the square of side 12 cm is cut on diagonal . Find the perimeter of triangle so formed

Answer 1

H of triangle=12
B of triangle=12

Area of a triangle =1/2*B*H
=1/2*12*12
=72 cm square.
IS IT CORRECT...!!!!

Answer 2

Answer:

40.97

Step-by-step explanation:

Diagonal of square = $\sqrt{2} a$

Where a is the side

So, diagonal of given square = $\sqrt{2} \times 12$

                                                = $16.97$

Now we are given that the square of side 12 cm is cut on diagonal

So, the height of triangle = side of square =12 cm

base of triangle = side of square =12 cm

Perimeter of triangle = Sum of all sides = 12+12+16.97 = 40.97

Hence the perimeter of triangle so formed is 40.97