Question

The square root of sum of the digits in the square of
121 is
(1) 4 (2) 3
(3) 6 (4) 9

Answer 1

square of 121 = 121 × 121 = 14641

sum of digits of square of 121 =  sum of digits of  14641 =  1 + 4 + 6 + 4 + 1 = 16

sum of digits of  14641  = 16 which is square of 4.

hence required solution is 4

Answer 2

Square root of 121 is (11)