the sum five times a number and six times the number is 11 less than 121. find the number.
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Answered by
1
Let the no. be x
A/Q 121 - (5x+6x) = 11
121 - 11x = 11
121 - 11 = 11x
11x = 110
x =![\frac{110}{11} \frac{110}{11}](https://tex.z-dn.net/?f=+%5Cfrac%7B110%7D%7B11%7D+)
x = 10
A/Q 121 - (5x+6x) = 11
121 - 11x = 11
121 - 11 = 11x
11x = 110
x =
x = 10
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Answered by
1
sup: number is x
so 5x+6x=11-121
11x= -110
x= -10
so 5x+6x=11-121
11x= -110
x= -10
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