Question

The sum of 2008 and number a is divisible by 13 and 19. Find the smallest value of number a.​

Answer 1

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Solution:

L.C.M. of 4, 9 and 10 is 180.

Prime factors of 180 = 2 x 2 x 3 x 3 x 5

Here, prime factor 5 has no pair. Therefore 180 must be multiplied by 5 to make it a perfect square.

\therefore180\times5=900∴180×5=900

Hence, the smallest square number which is divisible by 4, 9 and 10 is 900.

Answer 2

Answer:

$\huge\mathcal\fcolorbox{purple}{lavenderblush}{❥Answer}$

Solution:

L.C.M. of 4, 9 and 10 is 180.

Prime factors of 180 = 2 x 2 x 3 x 3 x 5

Here, prime factor 5 has no pair. Therefore 180 must be multiplied by 5 to make it a perfect square.

\therefore180\times5=900∴180×5=900

Hence, the smallest square number which is divisible by 4, 9 and 10 is 900.

Answer 3

Answer:

$\huge\mathcal\fcolorbox{purple}{lavenderblush}{❥Answer}$

Solution:

L.C.M. of 4, 9 and 10 is 180.

Prime factors of 180 = 2 x 2 x 3 x 3 x 5

Here, prime factor 5 has no pair. Therefore 180 must be multiplied by 5 to make it a perfect square.

\therefore180\times5=900∴180×5=900

Hence, the smallest square number which is divisible by 4, 9 and 10 is 900.