Question

The sum of 3 consecutive even numbers is 132. What is the third number in this sequence?

Answer 1

Let the 3 consecutive even numbers be x, (x-2) and (x+2) respectively.

According to the question,

x + (x - 2) + (x + 2) = 132

or, x + x - 2 + x + 2 = 132

or, 3x = 132

or, x = 132 ÷ 3

or, x = 44

So, first even number = 44

Required third number = 44 + 2

= 46 (Answer)

Answer 2

The third number in the sequence is 46

Given :

The sum of 3 consecutive even numbers is 132

To find :

The third number in the sequence

Solution :

Step 1 of 3 :

Form the equation

Let consecutive even numbers are x , x + 2 , x + 4

By the given condition

$\displaystyle \sf{ x + (x + 2) + (x + 4) = 132}$

Step 2 of 3 :

Find the value of x

$\displaystyle \sf{ x + (x + 2) + (x + 4) = 132}$

$\displaystyle \sf{ \implies 3x + 6 = 132}$

$\displaystyle \sf{ \implies 3x = 132 - 6}$

$\displaystyle \sf{ \implies 3x = 126}$

$\displaystyle \sf{ \implies x = \frac{126}{3} }$

$\displaystyle \sf{ \implies x = 42 }$

Step 3 of 3 :

Find third number in the sequence

First number = x = 42

Second number = x + 2 = 42 + 2 = 44

Third number = x + 4 = 42 + 4 = 46

Hence third number in the sequence = 46

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