The sum of 3 consecutive multiples of 4 is 252.Find the multiples
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Answered by
2
let three multiples of 4 be taken as
x , x*4 and x*4*4
adding all we get,
x+x×4+x×4×4= 252
3x+ 4×4×4= 252
3x+ 64= 252
3x= 252-64
3x= 198
x= 198/3= 66
Therefore, x= 66
x×4= 264
x×4×4= 4224
x , x*4 and x*4*4
adding all we get,
x+x×4+x×4×4= 252
3x+ 4×4×4= 252
3x+ 64= 252
3x= 252-64
3x= 198
x= 198/3= 66
Therefore, x= 66
x×4= 264
x×4×4= 4224
Dsnyder:
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Answered by
1
Let first multiple of 4 is 4x
second=8x
third=12x
4x+8x+12x=252
24x=252
x= 10.5
first multiple 4x= 42
second multiple =8x=84
third multiple=12x =126
Hope this helps
second=8x
third=12x
4x+8x+12x=252
24x=252
x= 10.5
first multiple 4x= 42
second multiple =8x=84
third multiple=12x =126
Hope this helps
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