the sum of 3 consecutive multiples of 6 is 72 the biggest of these 3 multiples solve it with linear equation.....
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Let the 3 multiples be x, x+6, x+12
Then,
x+x+6+x+12=72
3x+18=72
3x=72-18
3x=54
x=54/3
x=18
Therefore the three numbers are 18,18=6,18=12
=18,24,30
Largest multiple is 30
Then,
x+x+6+x+12=72
3x+18=72
3x=72-18
3x=54
x=54/3
x=18
Therefore the three numbers are 18,18=6,18=12
=18,24,30
Largest multiple is 30
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8
Heya !
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Your answer is in the pic.
Hope you find my answer useful and hope you mark my answer as brainliest !
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GeniusYH:
thanks
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