Question

the sum of 3 consecutive multiples of 7 is 777.find these multiples.(hint:3 consecutive multiples of 7 are x,x+7,x+14)

Answer 1

I assume them to be a-7, a, a+7. Now, (a-7)+(a)+(a+7)=777 → a=259.
Then three consecutive multiple of 7 are 252, 259, 266.

Answer 2

Let 1st multiple of 7 be (7x)----- then:-2nd=7(x+1)--------and the 3rd=7(x +2)so------ 7x + 7x +7 + 7x + 14= 777--------21x + 21= 777---- 21x=777-21----- 21x = 756------ X=756÷21=36----x = 36 1st multiple =7 × 36 =252------2nd multiple =252+7=259---- 3rd multiple =252+14 =266