Question

the sum of 3 consecutive Terms of an A.P. is 15 and sum of their square is 83. find the terms.​

Answer 1

Answer:

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Answer 2

Let the three numbers in A.P. be

a−d,a,a+d Sum=3a=15

a=5 Sum of their squares=(a−d) ²+

a²+ (a+d)² =83

3a² + 2d²=83

2d ² =83−3×25

d² =4 or d = ±2

Hence the numbers are 3,5,7 or 7,5,3