the sum of 3rd and 7th terms of an ap is 6 and their product is 8 find the sum of first 16th term of the AP and the a and D of product of AP
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Step-by-step explanation:
a3 +a7 =6
a +2d +a+6d=6
a+4d =3
a =3-4d ----(1)
a3 x a7 = 8
(a+2d)(a+6d) =8
Subtituiting.(1)...
(3-4d +2d)(3-4d+6d)=8
(3-2d)(3+2d) = 8
9-4d^2 =8
d = 1/2
Therefore... a =1
S16= 16/2(2x1+15x1/2)
= 8(2+15/2)
= 4x19
= 76
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