Question

the sum of 4 consecutive integers is 70 then the greatest among them is

Answer 1

Let the integers be x, (x +1),(x + 2), (x +3)

Given sum of them =70

x+(x +1)+(x + 2)+(x + 3) =70

4x + 6 =70

4x =64

x =64/4=16

Therefore, the consecutive integers are 16,17,18,19.

The largest among them is 19

Answer 2

Hello

Its ur answer

Let first number be x.
the second number will be x+1
the third no = x+1+1 = x+2
The fourth no = x+1+1+1 = x +3




According to the question,

The sum of 4 consecutive numbers is 70.

So,  
x + (x+1) + (x+2) + (x+3) = 70
4x + 6 = 70
4x = 64

x = 16.
So, x+1= 17
x+2= 18
x+3= 19

Hence, the greatest number among them is 19.




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