Question

the sum of 4 consecutive odd numbers is 56 . find the greatest of the 4 numbers.

Answer 1

Answer:

Required consecutive odd numbers are 11 , 13 , 15 , 17 .

Step-by-step explanation:

Let the required consecutive odd numbers are 2a + 1 , 2a + 3 , 2a + 5 , 2a + 7.

According to the question :

= > sum of the given odd numbers = 56

= > ( 2a + 1 ) + ( 2a + 3 ) + ( 2a + 5 ) + ( 2a + 7 ) = 56

= > 2a + 1 + 2a + 3 + 2a + 5 + 2a + 7 = 56

= > 2a + 2a + 2a + 2a + 1 + 3 + 5 + 7 = 56

= > 8a + 16 = 56

= > 8a = 56 - 16

= > 8a = 40

= > a = 40 / 8

= > a = 5

Therefore the required consecutive odd numbers are :

2x + 1 = 2( 5 ) + 1 = 10 + 1 = 11

2x + 3 = 2( 5 ) + 3 = 10 + 3 = 13

2x + 5 = 2( 5 ) + 5 = 10 + 5 = 15

2x + 7 = 2( 5 ) + 7 = 10 + 7 = 17

Answer 2

Answer :

The required consecutive odd numbers are 11, 13, 15, 17.

Step - by - step explanation :

Let the required consecutive odd numbers be x + 1, x + 3, x + 5 and x + 7.

According to the question ;

• x + 1 + x + 3 + x + 5 + x + 7 = 56

⇒ 4x + 16 = 56

⇒ 4x = 56 - 16

⇒ 4x = 40

⇒ x = 40 / 4

⇒ x = 10

Therefore, required consecutive odd numbers are ;

• ( x + 1 ) = 10 + 1 = 11

• ( x + 3 ) = 10 + 3 = 13

• ( x + 5 ) = 10 + 5 = 15

• ( x + 7 ) = 10 + 7 = 17.

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Thanks for the question !