Question

the sum of 4th and 8th term of an ap is 24 and the sum of the 6th and 10th term is 44 find the first three terms of an ap​

Answer 1

Step-by-step explanation:

a4+a8= 24

or a+3d+a+7d=24. ( an= a +(n-1))

2a + 10d = 24.

a+5d = 12. by taking 2 out from both sides

let the above equation be eq. no. 1

similarly 2a+ 14d = 44

a+ 7d= 22

let the above equation be eq no. 2

subtracting eq no. 1 from eq no. 2

we get

2d =10

d=5

substituting d=5 in eq no.1

we get

a+ 5*5= 12

a+25=12

a = -13

therefore

a2 = a+d

= -13 + 5

= -8

a3= a+ 2d

= -13 + 10

= -3