Question

the sum of 4th term and the 8th term of ap is 24 and the sum of the 6th term and the 10th term is 44. find the first three terms of the ap

Answer 1

Let the first term of an A.P = a and the common difference of the given  A.P = dAs we know that  a n = a+(n-1) d a 4 = a +( 4-1) d a 4 = a+3d Similarly ,  a 8 = a + 7 d a 6  = a + 5 d a 10 = a+ 9d Sum of 4 th and 8th terms of an A.P = 24 ( given ) a 4 +a 8 = 24 a + 3d + a + 7d = 24 2a + 10 d = 24 a +5d = 12  .....................(i) Sum of 6 th and 10 th term  of an A.P = 44 ( given ) a 6 +a 10 = 44 a + 5d +a+ 9d = 44 2a + 14 =44 a + 7d = 22  .....................(ii) Solving (i) & (ii)a +7 d  = 22 a + 5d = 12 -   -       -

2d  = 10 d = 5 From equation (i) ,  a + 5d = 12a + 5 (5) = 12 a+2 5= 12 a = - 13 a 2 = a+d = -13+5 = -8 a 3 = a 2 + d = -8+5 = -3 -13 ,-8,-3
hope you are satisfied....
plz mark as brainiest..... :)

Answer 2

:::::::::::::::::###:::Hy frnd::###:::::::::::::::::::
Hope this helps you
PLZZ MARK AS BRAINLIEST....; ^