The sum of a 2 Digit number and number obtained by reversing the order of digits is 90. if the digits of the number differ by 3. find the number.
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Let the two digit number = XY.
Therefore,
X - Y = 3 -----------Equation (1)
Also by the given condition ( 10X + Y ) + ( 10Y + X ) = 99.
11X + 11Y = 99
11 ( X + Y ) = 99.
X + Y = 9-----------Equation (2)
Adding equation (1) and equation (2) , we get
2X = 12
X = 6
Therefore,
6- Y = 3
-Y = -3
Y = 3.
Required number = 63
Therefore,
X - Y = 3 -----------Equation (1)
Also by the given condition ( 10X + Y ) + ( 10Y + X ) = 99.
11X + 11Y = 99
11 ( X + Y ) = 99.
X + Y = 9-----------Equation (2)
Adding equation (1) and equation (2) , we get
2X = 12
X = 6
Therefore,
6- Y = 3
-Y = -3
Y = 3.
Required number = 63
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