The sum of a no and its recipocal is 10/3 find the no
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let the no. be x
x+1/x=10/3
x^2+1=10x/3 (multiplying whole by x)
3x^2+3=10x ( multiplying whole by 3)
3x^2-10x+3=0
3x^2-9x-x+3=0
3x(x-3)-1(x-3)=0
3x-1=0 x-3=0
x=1/3 x=3
no. is 1/3 or 3
x+1/x=10/3
x^2+1=10x/3 (multiplying whole by x)
3x^2+3=10x ( multiplying whole by 3)
3x^2-10x+3=0
3x^2-9x-x+3=0
3x(x-3)-1(x-3)=0
3x-1=0 x-3=0
x=1/3 x=3
no. is 1/3 or 3
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