Question

The sum of a number b and twice the same number is 66.

Answer 1

Answer:We are given a+b+c=66, b=2a, and b=c-6.

We can solve for a and c in terms of b, so a=b/2, c=b+6.

Now, substitute a and c into the first equation, so b/2 + b + b+6 = 66, so (5/2)b=60, and b=24. Now solving for a and c gives a=b/2=12 and c=b+6=30.