the sum of a two digit number and the no. formed by interchanging the digits is 110.if 10 is subtracted from the first no.,the new number is 4 more than 5 times the sum of the digits in the first number.Find the number.
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let 2 digit no. be = 10x + y
case 1 =
10x + y + 10y + x = 110
11x + 11y = 110
11(x + y) = 110
x + y = 10 - 1)
case 2 =
10x + y - 10 = 5(x + y) + 4
10x + y - 10 = 5x + 5y +4
5x - 4y = 14
from eq 1) , y = 10 - x
5x - 4(10 - x) = 14
5x - 40 + 4x = 14
9x = 54
x = 6
In eq. 1)
y = 10 - x
y = 10 - 6
y = 4
Req. no. = 10x + y = 64
case 1 =
10x + y + 10y + x = 110
11x + 11y = 110
11(x + y) = 110
x + y = 10 - 1)
case 2 =
10x + y - 10 = 5(x + y) + 4
10x + y - 10 = 5x + 5y +4
5x - 4y = 14
from eq 1) , y = 10 - x
5x - 4(10 - x) = 14
5x - 40 + 4x = 14
9x = 54
x = 6
In eq. 1)
y = 10 - x
y = 10 - 6
y = 4
Req. no. = 10x + y = 64
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