the sum of a two digit number and the number formed by reversing the order of digits is 66 if the two digit differ by 2 find the number how many such number are there
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Let the two no. X and Y
x-y= 2. ------1
10x+y +10y +X = 66
11x +11y =66
X+y =6-----2x
solve equations 1 and 2
x-y=2
X+y=6
2x =8
X=4 put value of X in eq 1 then y = 2
Then the no. are 42
I hope this answer is correct
x-y= 2. ------1
10x+y +10y +X = 66
11x +11y =66
X+y =6-----2x
solve equations 1 and 2
x-y=2
X+y=6
2x =8
X=4 put value of X in eq 1 then y = 2
Then the no. are 42
I hope this answer is correct
gungun78:
ya this answer is correct
yes
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