The sum of a two-digit number and the
number obtained by interchanging the digits
is 143. If the digit at the units place is 3 more
than the digit at the tens place, find the
priginal number.
Answers
Answered by
3
Answer:
xy be the number
(10x+y)+(10y+x)=143 》x+y=13
also from given
y-x=3
solving the above 2 equations we will get y=8
and x=5
original number=58
Answered by
1
Answer:
143*3=429. is the and
hope it helps you
Anonymous:
hii
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