Math, asked by khushkaranjit, 1 year ago

The sum of all numbers between 800 and 1100 which are divisible by 79 is

Answers

Answered by puthoor07

9

first term a=869

last term l=Tn=1027

d=79

Tn=a+(n-1)d

1027=869+(n-1)79

1027=869+79n-79

1027=790+79n

1027/79=10+n

13=10+n

n=3

Sn=n/2 (a+l)

S3=3/2 (869+1027)

=3/2 (1869)

=3*984

S3=2844

Answered by 2580478

3

Answer:1896

Step-by-step explanation:

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